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| Orange Park 2025 / USA, ceglasta , ATP Orange Park 2025 Tenis live pula nagród: 15 tys. USD |
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| May 4, 2025 16:10 |
finał | Zink Tyler (USA) [2] (370) | 63.75% | 2 | 6 | 7 | I H2H O AI | ||||
| McCormick Tristan (USA) [6] (665) | 36.25% | 0 | 3 | 6 (0) | |||||||
| May 3, 2025 19:00 |
półfinał | McCormick Tristan (USA) [6] (665) | 38.67% | 2 | 6 | 6 | 2.1 | I H2H O AI | |||
| Kennedy Jack (USA) (1633) | 61.33% | 0 | 2 | 4 | 1.67 | ||||||
| May 3, 2025 17:00 |
półfinał | Zink Tyler (USA) [2] (370) | 44.08% | 2 | 6 | 7 | 1.42 | I H2H O AI | |||
| Serrano Luis Tomas Antonio (Port) (956) | 55.92% | 0 | 3 | 6 (2) | 2.61 | ||||||
| May 2, 2025 17:00 |
ćwierćfinał | Zink Tyler (USA) [2] (370) | 63.75% | 2 | 6 | 6 | 1.33 | I H2H O AI | |||
| Grant William (USA) [8] (692) | 36.25% | 0 | 1 | 1 | 2.87 | ||||||
| May 2, 2025 17:00 |
ćwierćfinał | Kennedy Jack (USA) (1633) | 53.57% | 2 | 6 | 3 | 6 | 1.65 | I H2H O AI | ||
| Willwerth Benjamin (USA) (1248) | 46.43% | 1 | 2 | 6 | 3 | 2.07 | |||||
| May 2, 2025 17:00 |
ćwierćfinał | Serrano Luis Tomas Antonio (Port) (956) | 52.17% | 2 | 6 | 7 | 2.83 | I H2H O AI | |||
| Kingsley Cannon (USA) [4] (525) | 47.83% | 0 | 1 | 5 | 1.34 | ||||||
| May 2, 2025 17:00 |
ćwierćfinał | McCormick Tristan (USA) [6] (665) | 67.00% | 2 | 6 | 1 | 7 | 1.66 | I H2H O AI | ||
| Vilicich Bautista (Arg) (784) | 33.00% | 1 | 2 | 6 | 6 (6) | 2.06 | |||||
| May 1, 2025 18:25 |
1/8 finału | Kingsley Cannon (USA) [4] (525) | 48.08% | 2 | 6 | 6 | I H2H O AI | ||||
| Lilov Victor (USA) (855) | 51.92% | 0 | 0 | 2 | |||||||
| May 1, 2025 17:46 |
1/8 finału | Willwerth Benjamin (USA) (1248) | 49.03% | 2 | 7 | 7 | I H2H O AI | ||||
| Fenty Andrew (USA) (925) | 50.97% | 0 | 5 | 5 | |||||||
| May 1, 2025 17:00 |
1/8 finału | Zink Tyler (USA) [2] (370) | 44.93% | 2 | 6 | 6 | I H2H O AI | ||||
| Hance Keaton (USA) [WC] | 55.07% | 0 | 3 | 2 | |||||||
| May 1, 2025 16:10 |
1/8 finału | Grant William (USA) [8] (692) | 2 | 6 | 6 | I H2H O AI | |||||
| Rahman Yannik (USA) (1745) | 0 | 2 | 4 | ||||||||
| May 1, 2025 19:05 |
1/8 finału | Vilicich Bautista (Arg) (784) | 38.04% | 2 | 6 | 6 | I H2H O AI | ||||
| Tudorica Alvin Nicholas (Kan) [3] (460) | 61.96% | 0 | 1 | 2 | |||||||
| May 1, 2025 16:10 |
1/8 finału | Kennedy Jack (USA) (1633) | 53.71% | 2 | 4 | 6 | 6 | I H2H O AI | |||
| Dickerson Ryan (USA) [Q] (1298) | 46.29% | 1 | 6 | 1 | 2 | ||||||
| May 1, 2025 16:10 |
1/8 finału | McCormick Tristan (USA) [6] (665) | 60.22% | 2 | 6 | 6 | I H2H O AI | ||||
| Bynoe Evan (USA) [Q] (1231) | 39.78% | 0 | 3 | 3 | |||||||
| May 1, 2025 18:05 |
1/8 finału | Serrano Luis Tomas Antonio (Port) (956) | 57.80% | 2 | 6 | 6 | 1.46 | I H2H O AI | |||
| Johnston Noah (USA) (1633) | 42.20% | 0 | 4 | 2 | 2.43 | ||||||
| Apr 30, 2025 17:00 |
1. runda | Lilov Victor (USA) (855) | 50.00% | 2 | 6 | 7 | 1.33 | I H2H O AI | |||
| Roberts Justin (Bah) [Q] (2126) | 50.00% | 0 | 1 | 5 | 2.89 | ||||||
| Apr 30, 2025 16:00 |
1. runda | Johnston Noah (USA) (1633) | 59.32% | 2 | 6 | 6 | 1.12 | I H2H O AI | |||
| Benson Maxwell (USA) [Q] | 40.68% | 0 | 3 | 2 | 4.9 | ||||||
| Apr 30, 2025 16:25 |
1. runda | Willwerth Benjamin (USA) (1248) | 51.50% | 2 | 4 | 6 | 6 | 1.66 | I H2H O AI | ||
| Kirchheimer Strong (USA) [5] (606) | 48.50% | 1 | 6 | 2 | 3 | 2.06 | |||||
| Apr 30, 2025 19:50 |
1. runda | Grant William (USA) [8] (692) | 52.97% | 2 | 6 | 6 | 1.38 | I H2H O AI | |||
| Ponwith Nathan (USA) (816) | 47.03% | 0 | 2 | 2 | 2.68 | ||||||
| Apr 30, 2025 17:50 |
1. runda | Rahman Yannik (USA) (1745) | 54.58% | 2 | 1 | 7 | 6 | I H2H O AI | |||
| Charlton Joshua (Aus) (924) | 45.42% | 1 | 6 | 6 (3) | 2 | ||||||
| Apr 30, 2025 17:50 |
1. runda | Hance Keaton (USA) [WC] | 46.10% | 2 | 6 | 6 | 1.74 | I H2H O AI | |||
| Segura Matthew (USA) [WC] (2012) | 53.90% | 0 | 3 | 3 | 1.95 | ||||||
| Apr 30, 2025 20:30 |
1. runda | Dickerson Ryan (USA) [Q] (1298) | 40.84% | 2 | 6 | 7 | I H2H O AI | ||||
| Johns Garrett (USA) [1] (340) | 59.16% | 0 | 2 | 6 (9) | |||||||
| Apr 30, 2025 16:00 |
1. runda | Fenty Andrew (USA) (925) | 47.54% | 2 | 7 | 6 | 1.23 | I H2H O AI | |||
| Bobo Dakotah (USA) [Q] | 52.46% | 0 | 5 | 0 | 3.5 | ||||||
| Apr 30, 2025 20:51 |
1. runda | Tudorica Alvin Nicholas (Kan) [3] (460) | 55.97% | 2 | 6 | 6 | 1.12 | I H2H O AI | |||
| Lynch Adam (USA) [Q] | 44.03% | 0 | 3 | 1 | 5.01 | ||||||
| Apr 30, 2025 20:30 |
1. runda | Bynoe Evan (USA) [Q] (1231) | 44.86% | 2 | 6 | 2 | 7 | 3.4 | I H2H O AI | ||
| Von Der Schulenburg Jeffrey (Szwaj) [Q] (1183) | 55.14% | 1 | 3 | 6 | 6 (4) | 1.24 | |||||
| Apr 30, 2025 19:05 |
1. runda | McCormick Tristan (USA) [6] (665) | 59.20% | 2 | 6 | 6 | I H2H O AI | ||||
| Sonne Tobias (Arg) [Q] (1658) | 40.80% | 0 | 1 | 0 | |||||||
| Apr 30, 2025 18:05 |
1. runda | Kennedy Jack (USA) (1633) | 56.15% | 2 | 6 | 7 | I H2H O AI | ||||
| Fishback Ryan (USA) (755) | 43.85% | 0 | 3 | 6 (7) | |||||||
| Apr 29, 2025 19:10 |
1. runda | Zink Tyler (USA) [2] (370) | 52.73% | 2 | 6 | 6 | 1.14 | I H2H O AI | |||
| Satterfield Jack (USA) [WC] (1779) | 47.27% | 0 | 2 | 3 | 4.61 | ||||||
| Apr 29, 2025 18:50 |
1. runda | Kingsley Cannon (USA) [4] (525) | 47.60% | 2 | 6 | 6 | 1.16 | I H2H O AI | |||
| Dussault Maximus (USA) [WC] (1779) | 52.40% | 0 | 3 | 2 | 4.37 | ||||||
| Apr 29, 2025 19:10 |
1. runda | Serrano Luis Tomas Antonio (Port) (956) | 44.19% | 2 | 6 | 6 | 6 | 2.22 | I H2H O AI | ||
| Gima Sebastian (Rum) [7] (672) | 55.81% | 1 | 7 (0) | 1 | 3 | 1.56 | |||||
| Apr 29, 2025 18:15 |
1. runda | Vilicich Bautista (Arg) (784) | 46.15% | 2 | 6 | 6 | 2.06 | I H2H O AI | |||
| Arseneault Nicolas (Kan) (876) | 53.85% | 0 | 2 | 1 | 1.66 | ||||||
